Introduction
In this lesson, you will learn how to divide multiple-digit numbers that have a whole number or a decimal as an answer. Unfortunately, answers to division problems are not always whole numbers.
People around the world use different division algorithms or methods. This lesson will teach one method. Feel free to use the method that best works for you.
These videos illustrate the lesson material below. Watching the videos is optional.
- Dividing by a Single Whole Number (07:23 mins) | Transcript
- Division Algorithm (Answers with Decimals) (02:54 mins) | Transcript
- Repeating Decimals (05:57 mins) | Transcript
Dividing by a Single Whole Number
You will learn how to do division with multiple digits. This process is applicable for numbers that divide evenly, and those with decimal answers. If you are familiar with another algorithm or pattern, you are welcome to use it. The important thing is to understand what you are doing and why so you can apply it to real-world situations.
Steps for division:
- Put the number being divided (the dividend) under the box and the other number (the divisor) to the left of the box.
- Starting on the left, determine how many times the divisor can go into the first digit of the dividend.
- Write that number above the digit and subtract the product of that number and the divisor from the dividend.
- Repeat steps 2 and 3, moving to the right.
The same process of division is used, even with a decimal answer. Remember, you can always add 0’s after the decimal place on a number (for example: \(2 = 2.0 = 2.00\)). The following instructions will show how to divide with decimals.
Note: This process may be slow at first. Take your time learning to divide accurately. Studying and memorizing your 1-digit multiplication facts will speed up the process and help you as you follow the division steps.
Example 1
\(364\div 7\)
The goal is to divide 364 into 7 equal pieces. Start by creating a box to help you organize the problem. Put 364 under the box, and 7, the divisor, outside of the box: \(\nequire{enclose}7\enclose{longdiv}{364}\)
Start with the first number on the left. In this case, 3. How many sevens can go into three? The answer is zero, so either put the zero here or just leave it blank. Normally, you leave it blank.
Since seven does not go into three, look at the next number over. Now you’re looking at the number 36. How many times does 7 go into 36, or what multiplied by 7 is close to 36? From your multiplication facts, you know that \(7\times5=35\). Because 35 is close to 36 while still being less than 36, you can put a 5 in the tens column.
Figure 1
\(7\times5=35\), so subtract 35 from 36, which leaves 1.
Figure 2
Carry down the number in the next column to the right, which is four. Now you are working with 14.
Figure 3
How many times does 7 go into 14? Your multiplication facts tell you that \(2\times7=14\), so the answer is two. \(14-14=0\), and because you have 0, you know that you’re done with the problem. The answer is 52: \(364\div7=52\).
Figure 4
Consider why this works. When you multiply 5 and 7, it’s actually 50 multiplied by 7 because the 5 is in the tens column. When you subtract, you’re actually subtracting 350 from 364. You couldn’t use a number larger than five here because anything larger than a five in the tens place would give you too large of a number.
You want to know how much is left over, so you subtract 350 from 364. In the first example, you just brought down the four. You can do this because there’s really a zero under the four. The remaining 14 means there’s 14 that still needs to be divided by 7.
Example 2
\(\nequire{enclose}8\enclose{longdiv}{984}\)
\(984\div8\). Start with the column farthest to the left, which in this case is the hundreds column. 8 goes into 9 one time. \(1\times8=8\), and \(9-8=1\).
Figure 5
Bring the remaining one down the next number to the right.
Figure 6
After bringing down the 8, you have 18. How many times does 8 go into 18? \(8\times2=16\), which is less than 18 but close to it. Put a 2 in the tens place, subtract 16 from 18, and bring the next number down.
Figure 7
When you bring the next number down, you have 24.
Figure 8
\(8\times3=24\). Subtract 24 from 24, and you get a remainder of zero, meaning the answer is a whole number. \(984\div8=123\)
Figure 9
Division Algorithm
How can you find the answer to a division problem when the answer is not a whole number? If the answer is not a whole number, it will be a decimal.
Example 3
\(17\div5\)
From your multiplication facts, you know that \(5\times3=15\), and \(5\times4=20\). This means that \(17\div5\) is going to have an answer somewhere between three and four, but it’s not exactly three or four. The answer will have a decimal in it.
Start by creating a little box: \(\nequire{enclose}5\enclose{longdiv}{17}\)
Use the same division algorithm used in the previous section. Five does not go into one, so move on to the next number: 5 does go into 17. \(3\times5=15\), which is ideal because it is close to 17 but still smaller than 17. Now subtract: \(17-15=2\).
Figure 10
The answer means that \(17\div5\) gives you an answer of three with two pieces remaining.
Now you must figure out how to put the two remaining pieces into decimal form. Put a decimal after 17 because 17 is the same as 17.0. If you put a zero here, you can bring a zero down and continue doing the algorithm as before. Keep in mind that if you add a decimal to the number you are dividing, you must put a decimal in the final answer as well.
Figure 11
\(5\times4=20\), so put a four in the answer after the decimal place.
Figure 12
You estimated at the beginning that the answer would be somewhere between three and four, and it is.
Repeating Decimals
There are some division problems where the answer will continue to repeat forever.
Example 4
\(1\div3\) or \(\nequire{enclose}3\enclose{longdiv}{1}\)
If you solve this equation using the regular division algorithm, you know that three doesn’t go into one, so you put a decimal in the answer and next to the one. Now you pretend like the answer is 10. Three goes into 10 three times.
Figure 13
\(3\times3=9\), and when you subtract, you get one left over. Bring down another zero. Three goes into 10 three times, and \(3\times3=9\). When you subtract 9 from 10, you have 1 remaining. If you repeat the process again, you get the same answer, so you find that there’s a pattern going on.
Figure 14
You could continue doing this forever, and you would get a never-ending stream of threes. In this case, the answer is 0.333… The little dots after it mean that the number goes on forever. Another way you can show that the answer repeats is by putting a line over the three: \(0.\overline3\)
Example 5
\(\nequire{enclose}6\enclose{longdiv}{5}\)
Sometimes it’s not immediately obvious that the answer will repeat forever.
Six doesn’t go into five, so you put a decimal point and a zero: \(\nequire{enclose}6\enclose{longdiv}{5.0}\)
Six can go into 50. \(6\times8=48\), so there’s two left over from 50.
Figure 15
Add another zero to the decimal point and bring it down.
Figure 16
\(3\times6=18\), so you know that six goes into 20 three times. \(20-18=2\), so you’ll bring down another zero.
Figure 17
You didn’t see repetition in the first digit, but you see it in the second and third digits. If you continued on, you’d see the repetition forever, so you can write the answer with a bar over the three to show that the three repeats from here on out: \(0.8\overline{3}\)
Example 6
\(1\div7\)
A calculator will help demonstrate this example. You get a huge number when you plug this equation into the calculator: 0.1428571428571428571….

Figure 18
It doesn’t look like it’s repeating initially. However, you see that the string of numbers repeats the sequence 142857.
When you run across problems like this, it’s efficient to round to the nearest hundredth. In the example above, because the two in the thousandths position indicates rounding down, the answer would be 0.14.
Things to Remember
- Steps for division:
- Put the number being divided (the dividend) under the box and the other number (the divisor) to the left of the box.
- Starting on the left, determine how many times the divisor can go into the first digit of the dividend.
- Write that number above the digit and subtract the product of that number and the divisor from the dividend.
- Repeat steps 2 and 3, moving to the right.
- If you get to the end of the dividend and the problem isn't complete, add a decimal to the end with zeros so you can bring down additional numbers as needed.
- When adding a decimal to the dividend, a decimal must also be added to the answer.
- When rounding to the nearest hundredth place, if the number in the thousandths place is five or greater, round up. If the number is lower than five, round down.
Practice Problems
Evaluate the following expressions. Round to the nearest hundredth.- \(77 ÷ 2 = ?\) (Solution
- \(339 ÷ 4 = ?\) (Solution
- \(21 ÷ 8 = ?\) (Video Solution
- \(37 ÷ 3 = ?\) (Solution
- \(559 ÷ 6 = ?\) (Video Solution
- \(258 ÷ 7 = ?\) (Solution